Understand the idea
A violin’s width shows an estimated density within a group. Wide parts indicate values near many observations, not a larger measured value.
A small example
Two groups can have the same median while one is tightly clustered and the other spread out; their violin widths differ along the value axis.
Follow the code
Apply the idea to the supplied table. Read from top to bottom; the final line displays the result.
import matplotlib.pyplot as plt
import seaborn as sns
fig, ax = plt.subplots(figsize=(6, 4))
sns.violinplot(data=df, x="flavour", y="price", cut=0, ax=ax)
ax.set(title="Candy shop", xlabel="flavour", ylabel="price")
fig.tight_layout()
plt.show()What each part does
sns.violinplot- mirrored density by category
cut=0- do not extend beyond observed values
Your inputs
The editable setup on the right creates df. Run executes the setup and your work from top to bottom.
| candy | flavour | price | rating | shelf |
|---|---|---|---|---|
| Gummy Bear | fruity | 1.2 | 4.1 | A |
| Choco Pop | chocolate | 2.1 | 4.6 | B |
| Mint Bite | mint | 1.5 | 3.8 | A |
| Berry Loop | fruity | 2.8 | 4.4 | B |
| Cocoa Cube | chocolate | 3.4 | 4.9 | A |
| Lemon Drop | fruity | 1.8 | 4 | B |
Your task · Follow
- Using df, call sns.violinplot with flavour on x and price on y, using cut=0.
- Chart: title "Candy shop"; x "flavour"; y "price".
Hint
The smooth shape depends on a density estimate; tiny groups do not support strong tail claims.
Reveal solution
One way to do it. Keep any supplied setup in the editor and use this in the Your work section.
import matplotlib.pyplot as plt
import seaborn as sns
fig, ax = plt.subplots(figsize=(6, 4))
sns.violinplot(data=df, x="flavour", y="price", cut=0, ax=ax)
ax.set(title="Candy shop", xlabel="flavour", ylabel="price")
fig.tight_layout()
plt.show()