Understand the idea
Distinct values answer “which labels?”; a distinct count answers “how many different labels?”. Neither counts how often each label occurs.
A small example
For ["A", "B", "A"], unique() gives A, B; nunique() gives 2.
Follow the code
Apply the idea to the supplied table. Read from top to bottom; the final line displays the result.
df["flavour"].nunique()What each part does
df["flavour"]- Choose the column whose category values you want to count.
.nunique()- Count its distinct known values.
Your inputs
The editable setup on the right creates df. Run executes the setup and your work from top to bottom.
| candy | flavour | price | rating | shelf |
|---|---|---|---|---|
| Gummy Bear | fruity | 1.2 | 4.1 | A |
| Choco Pop | chocolate | 2.1 | 4.6 | B |
| Mint Bite | mint | 1.5 | 3.8 | A |
| Berry Loop | fruity | 2.8 | 4.4 | B |
| Cocoa Cube | chocolate | 3.4 | 4.9 | A |
| Lemon Drop | fruity | 1.8 | 4 | B |
Your task · Follow
- Using df, return the number of distinct non-missing values in flavour.
- Use: nunique().
Hint
nunique counts labels; unique returns the labels themselves.
Reveal solution
One way to do it. Keep any supplied setup in the editor and use this in the Your work section.
df["flavour"].nunique()Optional stretch
Run unique() too. How many items are in the result?